MATH SOLVE

3 months ago

Q:
# In the equation, t is a constant. If the equation has no real solutions, what could be the value of t? 2x^2 β 4x = t please help im struggling and my teacher doesnt teach me anything sooo

Accepted Solution

A:

2x^2-4x=t2x(x-2)=tif t=0: 0=2x(x-2)[tex] \frac{0}{2(x - 2)} = x[/tex]so, x=0if t is not=0:[tex]x = \frac{t}{2(x - 2)} [/tex]